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Leya [2.2K]
3 years ago
14

5) Which of these are intensive properties?

Chemistry
1 answer:
evablogger [386]3 years ago
6 0

Answer:

For number 5 it is the 2nd one some stants has a mass of 1.25 g And the 2nd 1 number 6It is the 1st 1A subject has a melting point of 40

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The surface forces that change the surface of the earth are:
pshichka [43]
Number one victory royal yaaa
5 0
3 years ago
A sample of air at 58.6 kPa is expanded from 250 mL to 655 mL. If thetemperature remains constant, what is the final pressure in
kati45 [8]

Answer:

<h2>22.366 kPa</h2>

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question

58.6 kPa = 58600 Pa

We have

P_2 =  \frac{58600 \times 250}{655}  =  \frac{14650000}{655}  \\  = 22366.4122... \\  = 22366

We have the final answer as

<h3>22.366 kPa</h3>

Hope this helps you

3 0
3 years ago
Electronic transitions (i.e., absorption of uv or visible light) of the conjugated molecule butadiene can be approximated using
dlinn [17]

Answer:

2.51 Angstroms

Explanation:

For a particle in a one dimensional box, the energy level, En, is given by the expression:

En = n²π² ħ² / 2ma²

where n is the energy level, ħ²  is Planck constant divided into 2π, m is the mass of the electron ( 9.1  x 10⁻³¹ Kg ), and a is the length of the one dimensional box.

We can calculate  the change in energy, ΔE, from n = 2 to n= 3  since we know the wavelength of the transition  ( ΔE = h c/λ ) and then substitute this value for the expresion of the ΔE for a particle in a box and solve for the  length a.

λ = 207 nm x 1 x 10⁻⁹ m/nm = 2.07 x 10⁻⁷ m      ( SI units )

ΔE = 6.626 x 10⁻³⁴ J·s x  3 x 10⁸ m/s  / 2.07 x 10⁻⁷ m

ΔE   = 9.60 x 10⁻¹⁹ J

ΔE(2⇒3) = ( 3 - 2 )  x  π² x ( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

9.60 x 10⁻¹⁹ J  =  π² x( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

⇒ a = 2.51 x 10⁻¹⁰ m

Converting to Angstroms:

a = 2.51 x 10⁻¹⁰ m x 1 x 10¹⁰ Angstrom / m = 2.51 Angstroms

6 0
4 years ago
The lowest whole number ratio of ions
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What is the type 1 binary compound for MgCl2
Yuri [45]

Answer:

Explanation:

magnesium chloride

8 0
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