112.5 g. The production of 50.00 g O2 requires 112.5 g H2O.
a) Write the partially balanced equation for the decomposition of water.
MM = 18.02 32.00
2H2O → O2 + …
Mass/g = 50.00
b) Calculate the <em>moles of O2
</em>
Moles of O2 = 50.00 g O2 × (1 mol O2/16.00 g O2) = 3.1250 mol O2
c) Calculate the <em>moles of water</em>
Moles of H2O = 3.1250 mol O2 × (2 mol H2O/1 mol O2)
= 6.2500 mol H2O
d) Calculate the mass of water
Mass of H2O = 6.2500 mol H2O × (18.02 g H2O/1 mol H2O)
= 112.5 g H2O
Answer: Option (A) is the correct answer.
Explanation:
Elements present in group 1 are known as alkali metals. Whereas elements present in group 2 are called alkaline earth metals and elements from group 11 to 12 are transition metals.
As it is known that metals have the ability to lose electrons in order to attain stability and electricity is the flow of electrons from one point to another.
Therefore, metals are good conductors of heat and electricity.
Thus, we can conclude that the statement it’s between groups 1 to 12 because it is metal best explains the probable position of the substance in the periodic table.
Answer:
87.5198
Explanation:
(43.65 * 87.05) + (48.25 * 87.93) + (8.11 * 87.50) = 8751.98
8751.98 / 100 = 87.5198
Density = Mass / Volume
Mass = Density * Volume
Mass = 45 * 7 * 8 * 10
Mass = 25,200 grams
sodium hydroxide (NAOH) a.k.a causic soda commonly used in labs.
- MOLAR MASS of naoh is 39.997 g/mol.
- It is dry hard brittle, white stocks in large fused opaque white-stone like masses having a dense crystalline fracture in small pellets/flakes.
- it is very delinquent and one of the strongest base , acts as a saponifying agent which is used in industrial purposes.
- It is an important industrial chemical as it is used on its own and is also used as a raw material in the production of other chemicals. The basis for the production of sodium hydroxide is the electrolysis of brine.
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