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horsena [70]
4 years ago
5

What is 2 / 9 x - 9 / 2im having a hard time solving this

Mathematics
1 answer:
vfiekz [6]4 years ago
7 0
Answer is 34 .2/9 × 9 /2 = 34
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The total points scored in a basketball game can be calculated using the expression 3c + 3. If c = 41, how many points total wer
Anuta_ua [19.1K]
3(41) + 3
= 123 + 3
= 126
4 0
3 years ago
Read 2 more answers
Solution to (x-2) (x+10) = 13
Grace [21]

Answer:

-11,3

Step-by-step explanation: using foil (x-2)(X+10)=x^2+8x-20

x^2+8x-20-13=13-13 X^2+8x-33=0 factoring you get (x+11)(x-3)=0 so x+11=0

x-3=0

x=-11,3

if you found this helpful please thank me

4 0
3 years ago
What is the value of x in theequation 2.5 (6x - 4) = 10 + 4 (1.5 +0.5 x)?
Zarrin [17]

Answer:

x = 2

Step-by-step explanation:

Let's solve your equation step-by-step.

2.5(6x−4)=10+4(1.5+0.5x)

Step 1: Simplify both sides of the equation.

2.5(6x−4)=10+4(1.5+0.5x)

(2.5)(6x)+(2.5)(−4)=10+(4)(1.5)+(4)(0.5x)(Distribute)

15x+−10=10+6+2x

15x−10=(2x)+(10+6)(Combine Like Terms)

15x−10=2x+16

15x−10=2x+16

Step 2: Subtract 2x from both sides.

15x−10−2x=2x+16−2x

13x−10=16

Step 3: Add 10 to both sides.

13x−10+10=16+10

13x=26

Step 4: Divide both sides by 13.  

x=2

5 0
3 years ago
Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
2 years ago
Determine the product (4.2×10^-1)+(5.7+10^-1)
Alenkasestr [34]

Answer: (D) 2.394 * 10^-1

Step-by-step explanation:

(4.2 * 10^-1) (5.7 * 10^-1)

= 2.394 * 10^-1

4 0
3 years ago
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