Answer:
,bn ljb ib
Step-by-step explanation:
Answer:
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
Step-by-step explanation:
We will resolve each statement to determine the events that has exactly 12 possible outcomes.
N = number of possible outcomes for a cube
Nc = number of possible outcomes for a coin
Nca = number of possible outcomes for the cards
i. rolling a number cube with sides labeled 1 through 6 and then rolling the number cube again
Nt = N × N
N = 6 ( cube has 6 possible outcomes and its rolled twice)
Nt = 6 × 6 = 36
ii. tossing a coin and randomly choosing one of 4 different cards.
Nt = Nc × Nca
Nc = 2 ( coin has two outcomes)
Nca = 4 ( 4 possible cards )
B = 2 × 4 = 8
iii. rolling a number cube with sides labeled 1 through 6 and tossing a coin.
N = N × Nc
N = 6 ( cube has 6 possible outcomes)
Nc = 2 (coin has two faces)
N = 6 × 2 = 12 (correct)
Iv. tossing a coin 6 times.
N = Nc^6
Nc = 2
N = 2^6 = 64
Therefore, the correct answer is iii.
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
9514 1404 393
Answer:
A. 57 7/9 ft³
Step-by-step explanation:
The volume of a rectangular prism (cuboid) is the product of its dimensions.
V = LWH
V = (4 1/3 ft)(3 1/3 ft)(4 ft)
If you drop the fractions, this becomes ...
V = (4 ft)(3 ft)(4 ft) = 48 ft³
You know the fractions add some amount to this, so you know the volume will be somewhat larger than 48 ft³. The only reasonable choice is A: 57 7/9 ft³.
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If you feel the need to compute the volume exactly, you can do so using improper fractions.
V = (13/3 ft)(10/3 ft)(4 ft) = 520/9 ft³ = 57 7/9 ft³
Answer:
volume = 73.3ft³
value = $194.4
Step-by-step explanation:
volume of prism = (½bh)l
=(½×4×4)×9.2
=73.6ft³
value of concrete
1ft³ : $4.00
73 .6ft³ : X
X : (73.6ft³ × $4.00) ÷ 1ft³
X : $294.4
Answer:
Step-by-step explanation:
Given the circumference of Circle K = π
circumference of Circle L = 4π
Ratio of their circumferences = Ck/Cl
Ratio of their circumferences = π/4π
Ratio of their circumferences = 1/4 = 1:4
For their radii
C = 2πr
for circle k with circumference π
π = 2πrk
1 = 2rk
rk = 1/2
for circle l with circumference 4π
4π = 2πr
4 = 2r
r = 4/2
rl = 2
ratio
rk/rl = 1/2/2
rk/rl = 1/4 = 1:4
for the areas
Area of a circle = πr²
for circle k
Ak = π(1/2)²
Ak = π(1/4)
Ak = π/4
for circle l
Al = π(2)²
Al = 4π
Ratio of their areas
Ak/Al = π/4/(4π)
Ak/Al = π/16π
Ak/Al = 1/16 = 1:16
