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Effectus [21]
3 years ago
12

Jack had 4 hours of school. He spent 45 minutes in the library and 12 hour on a science lecture and had a lunch break of 25 minu

tes. How much time is left for the school to get over? (Write the answer as a fraction.)
Mathematics
1 answer:
andre [41]3 years ago
7 0

Answer:

\dfrac{10}{4} \ hour

Step-by-step explanation:

Given that :

Jack had 4 hours of school.

He spent 45 minutes in the library

1/2 hour on a science lecture  and;

had a lunch break of 25 minutes

The objective is to determine how much time is left for the school to get over and we are to write the answer as a fraction.

In order to do that, we will have to convert the minutes into hours,

we all know that; 60 minutes = 1 hour.

Then,

45 minutes = (45/60)hour = 3/4 hour

25/60 minutes = 1/4 hour

Therefore, the amount of time left  for the school to get over is:

= 4 - (\dfrac{3}{4}+\dfrac{1}{2}+ \dfrac{1}{4})

=  \dfrac{16-(3+2+1)}{4}

= \dfrac{16-6}{4}

= \dfrac{10}{4} \ hour

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Is this all correct?
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\large -\frac{2}{3}x+3=\frac{2}{3}x+\frac{1}{3}
german

Answer:

\boxed {x = 2}

Step-by-step explanation:

Solve for the value of x:

-\frac{2}{3}x + 3 = \frac{2}{3}x + \frac{1}{3}

-Take \frac{2}{3}x and subtract it from -\frac{2}{3}x:

-\frac{2}{3}x + 3 -\frac{2}{3}x = \frac{2}{3}x - \frac{2}{3}x + \frac{1}{3}

-\frac{4}{3}x + 3 = \frac{1}{3}

-Subtract both sides and convert 3 to a fraction:

-\frac{4}{3}x + 3 - 3 = \frac{1}{3} - 3

-\frac{4}{3}x  = \frac{1}{3} - \frac{9}{3}

Since both \frac{1}{3} and \frac{9}{3} have the same denominator, then you would subtract the numerator:

-\frac{4}{3}x  = \frac{1 - 9}{3}

-\frac{4}{3}x  = \frac{8}{3}

-Multiply both sides by -\frac{3}{4}, which is the reciprocal of -\frac{4}{3}:

x = \frac{8}{3} (-\frac{3}{4})

x = \frac{-8(-3)}{3 \times 4}

x = \frac{24}{12}

-Divide 24 by 12:

x = \frac{24}{12}

\boxed {x = 2}

So, therefore, the value of x is 2.

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