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3 years ago

Which transformation causes the described change in the graph of the function y = cos x?

1 answer:

8 0

Horizontal Shrink: y = cos 2x or if the coefficient of x is greater than 1
Vertical Stretch: y = 2 cos x or if the coefficient if cos x is greater than 1
Horizontal Stretch: y = cos (1/2) x or if the coefficient of x is less than 1
Vertical Shrink: y = (1/2) cos x or the coefficient of cos x is less than 1

The base value is 1 since it is the original coefficient of x and cos x. The values would adjust depending on the original coefficients.

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3 years ago

What is the solution to (x + 8) > (2x + 10)? (–∞, –4) (–4, ∞) (–∞, 4) (4, ∞)

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Step-by-step explanation:

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3 years ago

WILL MARK BRAINLIEST, JUST HELP ME PLS

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Answer:

SAS theorem

Step-by-step explanation:

If $\frac{CE}{CB} = \frac{DC}{AC}$ and m∠ECD = m∠BCA, then the triangles are similar by the SAS theorem.

$\frac{EC}{BC} = \frac{14}{21} = \frac{2}{3}$ $\frac{DC}{AC} = \frac{18}{27} = \frac{2}{3}$

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2 years ago

WILL MARK BRAINIEST!!1 PLZ HELP!25 points!!! The coordinate grid shows points A through K. What point is a solution to the syste

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Answer:

A, C, D and K

Step-by-step explanation:

Inequalities:

y ≤ −2x + 10 and y >1/2x-2

Finding zeros for the first inequality:

x=0 ⇒ y= 10, point (0, 10)
y=0 ⇒ x= 5, point (5, 0)

Locating these 2 points and connecting to get the first line.

Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.

Finding zeros for the second inequality:

x=0 ⇒ y= -2, point (0, -2)
y= 0 ⇒ x= 4, point (4, 0)

Locating these points and connecting to get the second line.

Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.

Now we have the space of intersection of the above inequalities.

So the points in same section are the solution.

They are:

Points A, C, D and K

See attached for explanation

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3 years ago