Which transformation causes the described change in the graph of the function y = cos x?

1 answer:

8 0

Horizontal Shrink: y = cos 2x or if the coefficient of x is greater than 1
Vertical Stretch: y = 2 cos x or if the coefficient if cos x is greater than 1
Horizontal Stretch: y = cos (1/2) x or if the coefficient of x is less than 1
Vertical Shrink: y = (1/2) cos x or the coefficient of cos x is less than 1

The base value is 1 since it is the original coefficient of x and cos x. The values would adjust depending on the original coefficients.

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Graph the function f(x) = -3x - 2.

Elza [17]

Answer: slope is -3 and y-intercept is -2

Step-by-step explanation:

when x= 0, y=-2

when x=1, y=-5

i believe you have just to change the value of the letter x in the equation to find the value of y

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The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
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3 years ago

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densk [106]

Answer:

Step-by-step explanation:

Because if 1 apple=2$ then she need to sell 20 apples she now has 26$ meaning she has sold 13 of them so 26$

She needs 14 more$ remember the rule 1 apple=2$ so if she needs 14 more $ then that means 7 more apples=14$ And there's your answer 7 more apples.

Hope this helps have a great afternoon:)

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kakasveta [241]

Given that the total number of students that sent messages = 150 students

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