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lawyer [7]
2 years ago
7

Find the 7th term in the sequence -1, -3, -9,...

Mathematics
2 answers:
mestny [16]2 years ago
7 0

Answer:

The answer is 729

Step-by-step explanation:

to get the next term, the sequence multiples the previous number by -3

1 * -3 = -3

-3 * -3 = 9

and so on.

To get the 7th term:

-27 * -3 = 81 (5th term)

81 * -3 = -243 (6th)

-243 * -3 = 729 (7th)

Neporo4naja [7]2 years ago
6 0

Answer:

-729

Step-by-step explanation:

First, note that the sequence is increasing not linearly. Thus, this is a geometric sequence.

The explicit formula for a geometric sequence is:

x_n=a(r)^{n-1}

Where a is the first term, r is the common ratio, and n denote the nth term.

So, from the sequence, we can see that the first term a is -1.

Also, each subsequent term is 3 times that of the previous one. In other words, the common ratio r is 3.

Thus, substituting:

x_n=-(3)^{n-1}

So, to find the 7th term, substitute n for 7:

x_7=-(3)^{7-1}

Simplify:

x_7=-(3)^6\\x_7=-729

And that's our answer :)

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zimovet [89]

Answer:

P=\frac{1}{13,983,816}=7.2\ x\ 10^{-8}

Step-by-step explanation:

Consider the following characteristics of the problem:

The numbers that are selected are different between 1 and 49. This means that the same number is not repeated twice.

The order in which the selected numbers appear does not matter:

This means that (123) = (312)

With this in mind, we know that it is a problem of combinations without repetition. It is not calculated using permutations because in the permutations the order of selection is important, for example: (123) is not equal to (312)

The formula for calculating combinations without repetition is:

nCr=\frac{n!}{r!(n-r)!}

Where n is the number of "elements" you can choose and choose r from them

In this case:

n=49

r=6

So:

49C6=\frac{49!}{6!(49-6)!}

49C6=13,983,816\ outcomes

There are 13,983,816 possible results

This is the best method to calculate the number of possible outcomes.

<em><u>"Besides your method, is there another method to determine the number of outcomes?"</u></em>

Sure, make a list of the 13,983,816 different sets of 6 numbers.

To win it is necessary to obtain the 6 winning numbers in any order. The number of ways this can occur is calculated by combining 6 in 6

6C6=\frac{6!}{6!(6-6)!}=1

Finally the probability of winning is:

P=\frac{1}{13,983,816}=7.2\ x\ 10^{-8}

Note that the probability of winning is very close to 0. It is practically impossible to win the lottery, you will probably never win anything. Therefore it is better not to invest money in this

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2 years ago
5/12 multiplied by 3 in all
AVprozaik [17]
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3 years ago
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