<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Answer:
187 cm²
Step-by-step explanation:
The bottom rectangle area is easy, it is 15*9 = 135 cm².
To find the area of the triangle, you only need the base width and its height (you don't need the hypotenuse). You can then use the formula: area triangle is base times half height.
The base width is 15-7 = 8 cm
The height is 22-9 = 13 cm
So the area of the triangle is 13*8/2 = 52 cm²
Together with the 135 of the rectangle that sums to 52+135 = 187 cm².
Domain is the x and range is y so your domain is 2,3,4,5 and your range is 0 and 4
The final answer for this question is 591.28 cubic cm
Answer:
(b) 5k+1
Step-by-step explanation:
https://www.symbolab.com/solver/step-by-step/simplify%20%5Cfrac%7B30k%5E%7B2%7D%2B6k%7D%7B5k%2Bk%7D