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2 years ago

Will someone please help me here

Mathematics

1 answer:

grandymaker [24]2 years ago

7 0

$\bf a) \\\\\\ \begin{array}{ccll} miles&minutes\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 11&74\\ 1&x \end{array}\implies \cfrac{11}{1}=\cfrac{74}{x}\implies x=\cfrac{1\cdot 74}{11} \\\\\\ b) \\\\\\ \begin{array}{ccll} lbs&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 20&8\\ 1&x \end{array}\implies \cfrac{20}{1}=\cfrac{8}{x}\implies x=\cfrac{1\cdot 8}{20}$

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5,140 centimeters = decameters centimeters

Ahat [919]

Answer:

5.14 Decameters

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3 years ago

A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of

hram777 [196]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ Ratio of two angles are 6:13.

So, let the one angle be $\sf{6x}$ and another be $\sf{13x.}$

As we know that,

Sum of all interior angles of a quadrilateral = $\sf\pink{360°.}$

So let's sum up the given angles,

$\rightarrow$ $\sf{222°+81°+6x+13x \:=\: 360°}$

$\rightarrow$ $\sf{303+19x \:=\: 360°}$

$\rightarrow$ $\sf{19x \:=\: 360-303}$

$\rightarrow$ $\sf{19x \:=\: 57}$

$\rightarrow$ $\sf{x \:=\: \frac{19}{57}}$

$\rightarrow$ $\sf{x \:=\: 3}$

Hence, $\sf{x \:=\: 3}$

So, First angle $\sf{= \:6x\: = \:6×3 \:=}$ $\sf\purple{18°.}$

Second angle $\sf{= \:13x\: = \:13×3 \:=}$ $\sf\purple{39°.}$

_________________________________

Hope it helps you:)

3 0

2 years ago

I GIVE ANOTHER BRAINLIEST

dlinn [17]

Answer:

Answer Below

Step-by-step explanation:

Triangle #1

To solve this answer we need to multiply then divide by 2

$3$ x $8=24$

$24$ ÷ $2=12$

Triangle #2

Now we do the same thing!

$3$ x $8=24$

$24$ ÷ $2=12$

Rectangle #1

Now we solve for the rectangle!

$6$ x $8 = 48$

Now we add all these together!

$12 + 12 + 48 = 72$

The answer is D. 72 Square Units

8 0

2 years ago

Read 2 more answers

Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.

tester [92]

Given:

Polynomial is $3x^2+15x-56$ .

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

$3x^2+15x-56+(x-8)^2$

$=3x^2+15x-56+x^2-2(x)(8)+8^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

$=3x^2+15x-56+x^2-16x+64$

On combining like terms, we get

$=(3x^2+x^2)+(15x-16x)+(-56+64)$

$=4x^2-x+8$

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is $4x^2-x+8$ .

7 0

2 years ago

The Coffee Shop around the Corner (CS) is famous for its fresh-made muffins. Hank, the owner of CS, knows that the demand for mu

Anastasy [175]

Answer:

The responses to the given question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

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$2 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \48 \\\\$

$Afternoon\ \ \ \ \ \ \ \ \ \ \ 28 \\\\$

$Evening \ \ \ \ \ \ \ \ \ \ \ 14 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.4 \\\\$

$3 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 53 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24.8\\\\$

$Afternoon \ \ \ \ \ \ \ \ \ \ \ 33 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30.4\\\\Evening \ \ \ \ \ \ \ \ \ \ \ 17 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35.2\\\\$

$4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29\\\\$

$Afternoon\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.25\\\\Evening \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34.33333\\\\$

6 0

3 years ago