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navik [9.2K]
3 years ago
13

Will someone please help me here

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0

\bf a) \\\\\\ \begin{array}{ccll} miles&minutes\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 11&74\\ 1&x \end{array}\implies \cfrac{11}{1}=\cfrac{74}{x}\implies x=\cfrac{1\cdot 74}{11} \\\\\\ b) \\\\\\ \begin{array}{ccll} lbs&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 20&8\\ 1&x \end{array}\implies \cfrac{20}{1}=\cfrac{8}{x}\implies x=\cfrac{1\cdot 8}{20}

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meriva

Answer:

\large\boxed{x=-\dfrac{1}{5}}

Step-by-step explanation:

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4 years ago
HELP ME PLEASE
solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

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We can write an exponential function to model the situation.

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P(t)=A(r)^t

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Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}

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\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}

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3 years ago
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Find the gradient of the line Joining the points p(-2,6) and Q(3,-2)​
Rudiy27

Answer:

-  \frac{8}{5}

Step-by-step explanation:

\boxed{gradient =  \frac{y1 - y2}{x1 - x2} }

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Gradient of the line

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