Person 4 has a child with someone who is a carrier of CF. Complete a Punnett Square to determine the chance their offspring will

Question

Setler79 [48]

3 years ago

5

Person 4 has a child with someone who is a carrier of CF. Complete a Punnett Square to determine the chance their offspring will

have Cystic Fibrosis.

Biology

1 answer:

stealth61 [152] · Answer 1 · 2022-04-14T15:23:11+03:00

stealth61 [152]3 years ago

6 0

Answer:Each time two CF carriers have a child together, the chances are: 25 percent (1 in 4) the child will have CF. 50 percent (1 in 2) the child will be a carrier but will not have CF. 25 percent (1 in 4) the child will not be a carrier of the gene and will not have CF.