Answer:
x = 2 (For First question)
Step-by-step explanation:
8^ 1/6 * 2^x = 32^1/2
8^1/6 * 2^x 8^1/6 = 32^1/2/8^1/6
2^x = 32^1/2 / 8^1/6
2^x = 4
2^x = 2^2
x =2
Question 2:
Answer: 50
Step-by-step explanation:
8^1/3/5^-2
= 2/5^-2
= 2/1/5^2
= 2* 5^2/1
= 2 * 5^2
= 2 * 25
= 50
Answer:
202
Step-by-step explanation:
First, we can find the conjugate of (-9 -11i)
Given a complex number a + bi, the conjugate would be a - bi.
So, the conjugate of -9 -11i is -9 + 11i.
Now, we multiply!
(-9-11i)(-9+11i)
This resembles the special product (a+b)(a-b) which multiplies out to a^2 - b^2
To apply this we subtract the square of the second number from the first.
(-9)^2 - (11i)^2
81 - 121i^2
i^2 is -1, so we can substitute it in:
81 + 121 = 202
4.8 is the number ten times the value in 4.381
You’d use ur outside number (7) and place that in the first part of both your brackets. Then add your 5 to one bracket and you 8 to the other and boom
