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Natali5045456 [20]
3 years ago
7

Find (ƒ + g)(x) for the functions provided: ƒ(x) = 2x − 5, g(x) = 4x + 3

Mathematics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:  The correct option is

(A) (ƒ + g)(x) = 6x − 2.

Step-by-step explanation:  We are given to find the value of (f + g)(x) for the following functions :

f(x)=2x-5,\\\\g(x)=4x+3.

We know that

for any two functions p(x) and q(x), we have

(f+g)(x)=p(x)+q(x).

So, we get

(f+g)(x)\\\\=f(x)+g(x)\\\\=2x-5+4x+3\\\\=6x-2.

Thus, (f+g)(x)=6x-2.

Option (A) is CORRECT.

Ann [662]3 years ago
4 0
This is 4x + 3 + 2x - 5

= 6x - 2 answer
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A local school donated canned goods to help the community. Cans were packed into boxes each weighing 16.4 pounds. The volunteers
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Answer:

<h3>147.6 pounds of food</h3>

Step-by-step explanation:

Each box weighed 16.4pounds, if the volunteers packed 9 boxes, we need to calculate the total pounds of food collected. Using the equality postulate;

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2 years ago
Calculate the lengths of the 2 unlabeled sides. GJ?
sladkih [1.3K]

Answer:

Length of hypotenuse JH = 9.2 unit (Approx.)

Length of perpendicular JG = 6.5 unit

Step-by-step explanation:

Given:

Length of base GH = 6.5 unit

Angle of H = 45°

Find:

Length of perpendicular JG

Length of hypotenuse JH

Computation:

Using trigonometry function:

Tan θ = Perpendicular / Base

Tan 45 = Perpendicular / 6.5

1 = Perpendicular / 6.5

Perpendicular = 6.5

Length of perpendicular JG = 6.5 unit

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Length of hypotenuse JH = √42.25 + 425.25

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Length of hypotenuse JH = 9.1923

Length of hypotenuse JH = 9.2 unit (Approx.)

3 0
3 years ago
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