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Artyom0805 [142]
2 years ago
11

(2 tens 1 one)x10 in unit form and standard form

Mathematics
1 answer:
omeli [17]2 years ago
4 0

When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten

<h3>How to write the number in standard form?</h3>

The number expression is given as:

(2tens 1 one) x 10

2 tens is represented as:

2 * 10

1 one is represented as:

1 * 1

So, the number expression can be rewritten as:

(2tens 1 one) x 10 = (2 * 10 + 1 * 1) x 10

Evaluate the product

(2tens 1 one) x 10 = (20 + 1) x 10

Evaluate the sum

(2tens 1 one) x 10 = (21) x 10

Evaluate the product

(2tens 1 one) x 10 = 210

When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten

Using the above steps as a guide, we have:

  • (5 hundreds 5 tens) * 10 ⇒ 5 thousands and 5 hundreds ⇒ 5500
  • (2 thousands 7 tens) / 10 ⇒ 2 hundreds and 7 units ⇒ 207
  • (4 ten thousands 8 hundred) / 10 ⇒ 4 thousands and 8 tens ⇒ 4080

Read more about standard form at

brainly.com/question/19169731

#SPJ1

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Answer:

The equation representing how old Monique son is \mathbf{a = 2 + \dfrac{8}{21}(q-34)}

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

q(t) = \hat q \times t + q_o

where;

q_o = initial height of Monique's son

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So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

\hat q = 2 \dfrac{5}{8} \ in/yr

\hat q =  \dfrac{21}{8} \ in/yr

Then; from the equation q(t) = \hat q \times t + q_o

34 = \dfrac{21}{8} \times 0 + q_o

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The height of the son as a function of the age can now be expressed as:

q(t) = \dfrac{21}{8} \times t + 34

Then:

Making t the subject;

q - 34 = \dfrac{21}{8} \times t

t = \dfrac{8}{21}(q-34)

and the age of the son  i.e. ( a (in years)) is:

a = 2 + t

So;

\mathbf{a = 2 + \dfrac{8}{21}(q-34)}

SO;

if q (growth rate) = 50 inches tall

Then;

\mathbf{a = 2 + \dfrac{8}{21}(50-34)}

\mathbf{a = 2 + \dfrac{8}{21}(16)}

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

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Monique son will be 8 years at the time Monique is 50 inches tall.

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