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Tresset [83]
3 years ago
6

which expression is equal to 2 square root of 28 - 5 the square root of 63? a. -11 square root of 7, b. -37 the square root of 7

, c. the square root of -7, d. square root of 7
Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

<u>The correct answer is A. - 11 square root of 7.</u>

Step-by-step explanation:

We have the expression 2 √28 - 5 √ 63 and we have to find and equal expression.

Let's simplify it:

2 √28 - 5 √ 63

2 √7 * 4 - 5 √ 9 * 7 (28 is also equal to 7 * 4 and 63 is equal to 9 * 7)

2 * 2 √7  - 5 * 3 √ 7

4 √7 - 15 √7

- 11 √7

<u>The equal expression is A. - 11 square root of 7.</u>

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Answer:

y = 5x - 9

Step-by-step explanation:

y - y₁ = m(x - x₁), where (x₁, y₁) = (3, 6)

y - 6 = 5(x - 3)

y = 5x - 15 + 6

y = 5x - 9

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3 years ago
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Consider two circular swimming pools. Pool A has a radius of 22 feet, and Pool B has a diameter of 13.6 meters. Complete the des
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Answers:

13 42 m; B; 0.57 m

Step-by-step explanation:

Data:

Pool A:  r = 22 ft

Pool B: D = 13.6 m  

Calculations:

1. Radius of Pool A

r = 22 ft × (0.305 m/1 ft) = 6.71 m

2. Diameter of Pool A

D =2r = 2 × 6.71 = 13.42 m

The diameter of Pool A is 13.42 m.

3. Compare pool diameters

The diameter of Pool B is 13.6 m.

So, the diameter of Pool <u>B</u> is greater.

4. Compare circumferences

The formula for the circumference of a circle is

C = 2πr or C = πD

Pool A: C = 2π × 6.71 = 42.16 m

Pool B: r =    π × 13.6 = 42.73 m

Pool B - Pool A = 42.73 - 42.16 = <u>0.57 m </u>

The circumference is greater by <u>0.57 m.</u>

8 0
3 years ago
Hey guys I need some help, Ty :)
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The answer is 8! Hope that helps! Please give brainliest hehe
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In determining the quality of the hats in a used-hat bin, a grandmother selects the first four hats she can reach. Which samplin
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Kia wants to order a large pizza from Frank's Pizza. Each large cheese pizza costs  $8.75 and each additional topping costs $0.5
Afina-wow [57]
<h2>Hello!</h2>

The answer is: A. 8.75 + 0.50 x ≤ 15.00

<h2>Why?</h2>

By isolating the variable (x), we have:

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