If you see the below statements among the choices, then you can select these as the answers:
a.) 39 + 2k = 69
2k = 69 - 39
2k/2 = 30/2
k = 15
b.) 39 + 2k = 69
39 + 2(15) = 69
39 + 30 = 69
69 = 69
A: If the 1st side of the garden is x feet long then the other sides are 2x - 5. The perimeter is simply the measure of the distance around the triangle, so the length of all three sides added up. So the equation to find the perimeter (p) would be...
p = x + (2x+5) + (2x+5)
or
p = x + 2(2x+5)
This is actually an equation so the expression to represent perimeter would simply be...
x + 2(2x+5)
B: Since we know the equation for the perimeter and we know that we have 40 feet of fencing, then the equation to find the left over fencing would just be the length of fencing minus the perimeter...
40 - x + 2(2x+5) = the leftover amount of fencing
so the expression is...
40 - x + 2(2x+5)
Answer:
(fog)(-3)= 11
Step-by-step explanation:
we have from statement:
f(x) = 7x + 4
g(x) = x + 4
so we have:
(fog)(x)= 7(x+4) + 4
(fog)(-3)= 7(-3+4) + 4
(fog)(-3)= 7(1) + 4
(fog)(-3)= 11
Answer: sale: 536
discount: 33%
33/100*536=
Step-by-step explanation:
1- I assume the cost of the suit is $536, not 536%.
So the % of the part times $536= Original price
Remember, $536 is 77% of the original price.
536x0.77=$696.10
Since the suit was 33% off, and since the sale price of the suit was $536
Then the suit was sold for 67% of its original price
Therefore, 67% of its original price (p) equals $536, or .67(p) = 536
.67p = 536
p = 536 � .67 = $800
Original price of suit was $800
Answer:
The x-coordinate is \dfrac{\pi}{6}[/tex].
Step-by-step explanation:
We are given a function f(x) as:
Now on differentiating both side with respect to x we get that:
When 
this means that 
Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval ![[0,\pi]](https://tex.z-dn.net/?f=%5B0%2C%5Cpi%5D)
.
also we know that 
----(1) (which lie in the second quadrant)
so on comparing our equation with equation (1) we obtain:
Hence, the x-coordinates where for 
is 
.
