Answer:
y = - 2x + 8
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 9 ← is in slope- intercept form
with m =
given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= - 2
y = - 2x + c ← is the partial equation
to find c substitute (3, 2 ) into the partial equation
2 = - 6 + c ⇒ c = 2 + 6 = 8
y = - 2x + 8 ← equation of perpendicular line
The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).
