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3 years ago

Find the second of two consecutive even numbers whose sum is 798

1 answer:

7 0

To set up consecutive even integers you use x for the first integer and x + 2 for the second integer. You add 2 since you are going to the next EVEN instead of just the next integer. Now we set up an equation = 798 and solve.
x + x + 2 = 798
2x + 2 = 798
subtract -2 from both sides
2x = 796
divide by 2 on both sides
x = 398
x + 2 = 398 + 2 = 400
CHECK 398 + 400 = 798

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3 years ago

Determine the value of x if the sequence 2x-1; 3x+1; 7x-1; is a geometric sequence

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x=0 or x=3

Step-by-step explanation:

Since it is a geometric sequence, that means term divided by previous term is the same number. Let's call that number, r.

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Since both of the ratios are the same, then we have

(3x+1)/(2x-1)=(7x-1)/(3x+1)

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3 years ago

The set $\{2, 4, 6, \dots, n\}$ contains the positive consecutive even integers from 2 through $n$. When one of the integers fro

Vsevolod [243]

The least possible value of n is 27.

According to the statement

We have given that the set which is {2,4,6,8.....n} and and one set is removed from them the average of remaining integers is 28.

Then

Firstly set contain n numbers

But after that set contain n-1 numbers after removal of 1 digit from them.

and average value of remaining digit is 28 then 28th term become after removal is

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we use the formula to calculate n

n-1 =28

then the value of n become 27.

the least possible value of n is 27.

So, The least possible value of n is 27.

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