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3 years ago

What number is ten times greater than 0.3

Mathematics

2 answers:

noname [10]3 years ago

6 0

Answer:

The number is 3

Step-by-step explanation:

Step 1: Convert words into an expression

What number is ten times greater than 0.3

n = 10 * 0.3

Step 2: Multiply

n = 10 * 0.3

n = 3

Answer: The number is 3

blagie [28]3 years ago

3 0

Answer: 3

Step-by-step explanation:

The number ten times greater than 0.3 will be 0.3 in ten places

= 0.3 x 10

I hope this helps.

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3 years ago

Five crates weigh 200 pounds. One crate weighs 20 pounds but each of the other four crates weigh the same amount. What is the we

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3 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

Basile [38]

Answer:

$f(x) = x^3 - 2x^2 -3x + 6$

Step-by-step explanation:

According to the Factor Theorem, if (x - k) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let k = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

$\displaystyle f(x) = x^3 - 2x^2 - 3x + 6$

Testing all three values yields that:

$\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \end{aligned}$

Hence, our answer is A.

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3 years ago