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3 years ago

Write the following equation in standard form: 2/3a + 5a3 + 4a4 - 2a5

Mathematics

1 answer:

Ronch [10]3 years ago

3 0

Answer:

-2a^5 + 4a^4 + 5a^3 + 2/3 a

Step-by-step explanation:

Standard form for an expression is written in descending order according to the exponent on the variable. The term with the highest exponent is written first.

2/3 a + 5a^3 + 4a^4 - 2a^5 becomes -2a^5 + 4a^4 + 5a^3 + 2/3 a

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Step-by-step explanation:

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The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

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3 years ago

What are the zeros of the polynomial function f(x) = x^3-10x^2+24x

Ludmilka [50]

Replace F(x) with y
y=x^3-10x^2+24x
To find the roots replace y with 0.
0=x^3-10x^2-24x
Rewrite the equation as
x^3-10x^2+24x=0
Factor the left side
x(x-6)(x-4)=0
The solution is a result of
x=0, x-6=0, and x-4=0

The answer is:
x=0, 6, 4

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3 years ago

Is this statement always, sometimes, or never true.

cestrela7 [59]

Answer:

Never true

Step-by-step explanation:

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3 years ago

Write the following equation in standard form: 2/3a + 5a3 + 4a4 - 2a5​

Write the following equation in standard form: 2/3a + 5a3 + 4a4 - 2a5