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siniylev [52]
3 years ago
10

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

the component will survive past 5 years assuming:
(a) lambda=.5
Pr=_________
(b) lambda=0.9
Pr=_________
(c) lambda=1.1
Pr=_________
Mathematics
1 answer:
wlad13 [49]3 years ago
7 0

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \lambda e^{-\lambda x}

In which \lambda is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\lambda x}

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

In all 3 cases, we want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = 1 - e^{-5\lambda}

(a) lambda=.5

P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821

(b) lambda=0.9

P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111

(c) lambda=1.1

P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041

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