Answer:
The allelic frequencies in the population for "A" is 0.6 and for "a" is 0.4
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q²(Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example,
- Flightal (A) is dominant,
- Groundling (a) is recessive
- Heterozygotes are Hoverants.
- 16% of residents in the anti-parallel universe are groundlings
What are the allele frequencies in the population for A and a?
If 16% of residents are groundlings, this means that the genotypic frequency for the trait, aa, is 0.16.
If 0.16 is the genotypic frequency for groundlings, which is aa= q²= 0.16, then we can calculate the allelic frequency by clearing the equation:
if q²= 0.16, then q = √0.16 = 0.4
So now we know that he allelic frequency for a or q is 0.4
This means that the allelic frequency for A or p is 0.6, which we deduce by clearing the equation p + q = 1
p + 0.4 = 1
p = 1 - 0.4
p = 0.6
The allelic frequencies in the population for A is 0.6 and for a is 0.4
