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jasenka [17]
3 years ago
8

What is the distance between point P and point Q? 

Mathematics
1 answer:
kirill115 [55]3 years ago
4 0

Answer:

Option A. half the distance between point A and point K

Step-by-step explanation:

Ax=Fx

Fy=Ky

The distance between point A and point K is:

AK=Ax+Fx+Fy+Ky

Like Ax=Fx and Fy=Ky

AK=Fx+Fx+Fy+Fy

AK=2Fx+2Fy

Common factor 2:

AK=2(Fx+Fy)

The distance between point P and point Q is:

PQ=Fx+Fy

Then the distance between point P and point Q is half the distance between point A and point K:

PQ=Fx+Fy=AK/2=2(Fx+Fy)/2=Fx+Fy

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Find parametric equations which describe each curve. No particular orientation is required.
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Answer:

The equation of the line is (x(t),y(t))=(1-4t,2+6t) and the equation of the circle is F(t)= (3cos(t)+4,3sin(t)+1).

Step-by-step explanation:

(a) Given: The given points are (1,2) and (-3,8).

To find: The parametric equation of line containing points (1,2) and (-3,8).

We know that the parametric equation of line containing (x_{1} ,y_{1} ) and (x_{2} ,y_{2} ) is given by (x(t),y(t))=(x_{1}+(x_{2}-x_{1})t,y_{1}+(y_{2}-y_{1})t) where t∈[0,1].

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Hence, the required parametric equation of the line is (x(t),y(t))=(1-4t,2+6t).

(b) Given: The radius of circle is 3 and centre is (4,1).

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We know that parametric equation of circle with radius r and centre (h,k) is given by F(t)= (x(t),y(t)) where x(t)=rcos(t)+h and y(t)=rsin(t)+k.

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Hence, the required equation of the circle is F(t)= (3cos(t)+4,3sin(t)+1).

7 0
2 years ago
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Answer:

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Step-by-step explanation:

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Hope you got it.

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2 years ago
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Answer:

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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