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eduard
3 years ago
8

What is the solution to the equation 3 sqrt (5x-4) = 3 sqrt (7x+8) ? x = –6 x = –1 x = 1 x = 2

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

-6 = x

Step-by-step explanation:

3 sqrt (5x-4) = 3 sqrt (7x+8)

Divide each side by 3

3/3 sqrt (5x-4) = 3/3 sqrt (7x+8)

 sqrt (5x-4) = sqrt (7x+8)

Square each side

 (sqrt (5x-4))^2 = ( sqrt (7x+8) )^2

5x-4 = 7x+8

Subtract 5x from each side

5x-5x-4 = 7x-5x+8

-4 = 2x+8

Subtract 8 from each side

-4-8 = 2x+8-8

-12 = 2x

Divide by 2

-12/2 = 2x/2

-6 = x

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Y = x3 + x2 − 4x − 16
ICE Princess25 [194]

Answer:

use photo math

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Each day a manufacturing plant receives a large shipment of drums of Chemical ZX-900. These drums are supposed to have a mean fi
nikdorinn [45]

Answer:

0.9544 = 95.44% probability that the average fill for the 100 drums is between 49.88 and 50.12 gallons.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Suppose the mean fill for the shipment is actually 50 gallons. Standard deviation of 0.6 gallons.

This means that \mu = 50, \sigma = 0.6

Sample of 100:

This means that n = 100, s = \frac{0.6}{\sqrt{100}} = 0.06

What is the probability that the average fill for the 100 drums is between 49.88 and 50.12 gallons?

This is the pvalue of Z when X = 50.12 subtracted by the pvalue of Z when X = 49.88. So

X = 50.12

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{50.12 - 50}{0.06}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 49.88

Z = \frac{X - \mu}{s}

Z = \frac{49.88 - 50}{0.06}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the average fill for the 100 drums is between 49.88 and 50.12 gallons.

7 0
3 years ago
What is the solution to the equation?
KonstantinChe [14]
Answer: D
1/2x-1+4=x
1/2x-x=-3
-1/2x=-3
x=6
4 0
3 years ago
Read 2 more answers
How do u do this? Help plz
aniked [119]
P=2250e^(rt)
P/2250=e^(rt)
ln(P/2250)=ln(e^(rt))
ln(P/2250)=rt
r=ln(P/2250)/t
6 0
4 years ago
In the library at Lenape Elementary School, there are
Phoenix [80]

Solution:

we are given that

In the library at Lenape Elementary School, there are 3/8 as many fiction books as there are nonfiction books.

There are 44 books in the school library.

we have been asked to find How many books are fiction books?

Let there are x non fiction books in the library. Then there will be \frac{3}{8}x fiction books.

Hence we can write

x+\frac{3}{8}x=44\\\\\text{Now solve for x}\\\\\frac{8x+3x}{8}=44\\\\\frac{11x}{8}=44\\\\11x=44*8\\\\x=\frac{44*8}{11}\\\\x=4*8=32\\

Hence there are 32 non-fiction books in the library.

and 44-32=12 fiction books in the library.

6 0
3 years ago
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