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4 years ago

(20 points)

2 answers:

8 0

V = (1/4)(π* d² * h)
V = (1/4)(π * 10² * 12) 
V = (1/4)(1200π) 
V = 300π 
[ V ≈ 942 cubic units . . . . . to 3 s.f. ] 
V ≈ 942 cubic units

Papessa [141]4 years ago

5 0

Answer:

Step-by-step explanation:

It is given that a cylinder has a base diameter of 10, then the radius of the cylinder will be 5.

Also, it is given that the height of the cylinder is 12, then

Volume of cylinder is given as:

$V={\pi}r^2h$

$V=3.14{\times}(5)^2{\times}12$

$V=3.14{\times}25{\times}12$

$V=78.5{\times}12$

$V=942.0 cubic units$

Therefore, the volume of the cylinder is 942 cubic units.

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How many centimetres are they in two and a half metres

Irina-Kira [14]

250 centimeters and this is correct so don't delete answers for no reason thats against brainly's policy

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3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

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4 0

4 years ago

Please help and tell me which answer on the bottom is correct. I don't know how to do math..

Illusion [34]

Answer:

875

Step-by-step explanation:

30*15=450

30*10=300

20*5=100

12.5+12.5=25

450+300+100+25=875

I worked from bottom to top

3 0

3 years ago

Read 2 more answers

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

The height of two similar pails are 12cm and 8cm.The larger pail can hold 2litres. What is the capacity of the smaller pail?

Vedmedyk [2.9K]

Answer:

1.33 liters

Step-by-step explanation:

Volume of any shape is given by cross sectional area multiplied by height. Therefore, V=Ah

Where A is area and h is height

Since their cross sections are the same, then volume depends on height.

If 12cm equals 2 liters

8cm equals x

X=(2*8)/12=1.3333333333333 liters

Approximayely, the smaller pail has capacity of 1.33 liters

7 0

4 years ago