Answer:
<h2>please upload tge figure......</h2>
Answer:
Solution given:
opposite:9
adjacent: 12

Relationship between opposite and adjacent is given by tan angle
so




#11.
hypotenuse[h]=11cm
opposite/perpendicular[P]=b cm
adjacent/base[b]=a cm
now

Relationship between height and hypotenuse is given by Sin angle
:.
Sin 62°=
doing crisscrossed multiplication
b=Sin 62°*11
:.b=9.71 cm
a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.
again
Relationship between base and hypotenuse is given by Cos angle
:.Cos 62°=
doing crisscrossed multiplication
a=Cos 62°×11
a=5.16cm
b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
The first one would be (2x)(7) and plus the other 75 it would be 738 with that in total of it c 5 3-15
Answer:
- 7y +3 =-25
-7y=-25—3
-7y=-28
-7y÷-7= -28÷-7
y=4
Step-by-step explanation:
Take +3 to the side so that your variable and a constant is on their own sides. When a number goes over the equals sign the sign changes at becomes the inverse that's why l said - 3. You now calculate - 25—3 equals 28 then divide by 7 to find y and your y is 4.