Since the problem is 2x^2-5xy-y^3 we first have to plug in what the x and y stands for, once you do that your problem should look like this:
2(-3)^2- 5(-3)(-2)- (-2)^3
Now take the parentheses away and when you do that your signs change.
2x3^2-5x(-3)x(-2)-(-2)^3
do it again with -5x(-3)x(-2)
2x3^2-30-(-2)^3
now do this with (-2)^3
2x3^2-30-(-8)
Now evaluate the power
3^2 becomes 9
2x9-30-(-8)
then change -(-8) to a positive since two negatives make a positive
2x9-30+8
Now multiply the numbers 2x9
18-30+8
Then do 18-30 which equals -12 then add 8
Now you are left with your answer:
<u>-4</u>
Hope this helps! :3
Write the number out:
ex) 2 dots on number 3 so write number 3 twice and etc
3,3,4,5,5,5,6,8,8
find the middle number
5 is the middle number so it’s the median
So you first make 1 7/9 into 16/9
then you do 16/9 - 4/9 which equals to 12/9 then you simplify and get 4/3 then simplify again into 1 1/3
Answer:
The probability that he teleports at least once a day = 
Step-by-step explanation:
Given -
Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.
Total no of outcomes = 3
P( He not choose teleport in the morning ) = 
P( He not choose teleport in the evening ) =
P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )
= 1 - P( He not choose teleport in the morning ) 
P( He not choose teleport in the evening )
= 
= 
Answer:
52.9
Step-by-step explanation:
180-32.1-95=
guessing you don't have a calculater or the patience to answer this
