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BigorU [14]
3 years ago
12

Find the volume of a right circular cone that has a height of 14.3 ft and a base with a diameter of 17.2 ft. Round your answer t

o the nearest tenth of a cubic foot.

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

Volume of the given cone is 1107.6 cubic feet.

Step-by-step explanation:

Formula to get the volume of a right circular cone is,

V = \frac{1}{3}\pi r^{2}h

Here r = radius of the circular base

h = height of the cone

Now we put the values in the given formula

Volume = \frac{1}{3}\pi (8.6)^2(14.3)  [ radius = \frac{17.2}{2}=8.6 ]

             = \frac{1057.628\pi }{3}

             = 1107.55

             ≈ 1107.6 cubic feet

Therefore, volume of the given cone is 1107.6 cubic feet.

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3 years ago
Below are tabulated a number of Rockwell G hardness values that were measured on a single steel specimen. Compute
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Answer:

a) 48.408

b) 1.235

Step-by-step explanation:

a)

The average hardness value xbar can be computed as

xbar=sum of values/number of values

xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12

xbar=580.9/12

xbar=48.408 (rounded to 3 decimal places).

The average hardness value is 48.408.

b)

The standard deviation hardness value s can be computed as

s=\sqrt{\frac{sum(x-xbar)^2}{n-1} }

x              x-xbar  (x-xbar) ²

46.5  -1.90833 3.64174

46.9  -1.50833 2.27507

49.4    0.99167 0.98340

50.3     1.89167 3.57840

49.8     1.39167 1.93674

48.8    0.39167 0.15340

47.0           -1.40833 1.98340

47.7   -0.70833 0.50174

48.3           -0.10833 0.01174

49.4    0.99167  0.98340

47.8           -0.60833 0.37007

49.0    0.59167 0.35007

Total                               16.7692

s=\sqrt{\frac{16.7692}{12-1} }

s=\sqrt{\frac{16.7692}{11} }

s=\sqrt{1.5245}

s=1.2347

s=1.235 (rounded to 3 decimal places)

The standard deviation hardness value is 1.235.

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