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astra-53 [7]
3 years ago
14

Write an equation for the line perpendicular to y=2x 4 that contains (3, -2)?

Mathematics
1 answer:
murzikaleks [220]3 years ago
3 0
In the equation y = 2x + 4, you know that the gradient is 2 (the number before x).


for a perpendicular line you need the negative reciprocal of 2, which is - \frac{1}{2} .

you then need to use the equation
y - y_{1} = m(x - x_{1} )

substitute in your coordinates:

y - -2 = - \frac{1}{2} (x - 3)


simplify:
y + 2 = -0.5x + 1.5

rearrange:

y = - \frac{1}{2} x - \frac{1}{2}

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<img src="https://tex.z-dn.net/?f=%20%7C3%20-%20x%7C%20%20-%20%28x%20-%201%29%20%3D%204" id="TexFormula1" title=" |3 - x| - (x
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Answer:

x=0

Step-by-step explanation:

Evaluate all the arithmetic first, and then remember absolute value equations have two possible ways to go (+ and -).

You can see how I split them on the 3rd line, later demonstrating how the 2nd one is invalid.

|3-x|-x+1=4\\\\|3-x|-x=3\\\\3-x-x=3\\-(3-x)-x=3\\\\3-2x=3\\-3+x-x=3\\\\-2x=0\\-3\neq 3\\\\x=0\\-3\neq 3\\

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