Question

if 25 grams of silver chloride are reacted with 60 grams of magnesium nitrate, which is the limiting reactant

Answer 1

AgCl

Explanation:

Given parameters:

Mass of AgCl = 25g

Mass of Mg(NO₃)₂ = 60g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. This reactant determines the extent of the reaction because it is limited in supply.

To find this reactant, let us write the balanced equation of the reaction;

        2AgCl     +     Mg(NO₃)₂    →      2AgNO₃    +  MgCl₂

Convert the masses into number of moles;

  Number of moles = $\frac{mass}{molar mass}$

molar mass of AgCl = 108 + 35.5 = 143.5g/mol

molar mass of   Mg(NO₃)₂ = 24 + 2[(14 + 3(16)} = 158g/mol

Number of moles of AgCl  = $\frac{25}{143.5}$ = 0.17mole

Number of moles of  Mg(NO₃)₂ = $\frac{60}{158}$ = 0.38mole

    2 moles of AgCl reacted with 1 mole of  Mg(NO₃)₂

   0.17 mole of AgCl will require   $\frac{0.17}{2}$mole to react

                                      with it = 0.085‬mole of Mg(NO₃)₂

But we have been given 0.38mole of Mg(NO₃)₂ .  This is in excess.

The limiting reactant is AgCl

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