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marusya05 [52]
2 years ago
14

If 3.00 g of limestone reacted, what mass of calcium chloride would be produced?

Chemistry
1 answer:
Levart [38]2 years ago
8 0
CaCO₃ → CaCl₂
Ca = 40, C = 12, O = 16, Cl = 35.5
100 →111
3     →  x
x = 3.33g

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Which of the titanium-containing minerals rutile (TiO2) or ilmenite (FeTiO3) has the larger percentage of titanium?
cupoosta [38]

Rutile (TiO2) or ilmenite (FeTiO3) titanium-containing minerals  has the larger percentage of titanium is explained below.

Explanation:

1. Titanium is obtained from different ores that occur naturally on the Earth. Ilmenite (FeTiO3) and rutile (TiO2) are the most important sources of titanium.

2. According to USGS, Ilmenite(FeTio3) accounts for about 92% of the world’s consumption of titanium minerals.

3. World resources of anatase, ilmenite and rutile total more than 2 billion tonnes. Identified reserves total 750 million tonnes (ilmenite plus rutile).

4. China, with 20 million tonnes--accounting for 29% of the world total-- is now the country that is most abundant in terms of ilmenite reserves. Meanwhile, Australia, with 24 million tones rutile reserves—accounting for 50% of the world total—is now the country that is most abundant in terms of rutile reserves.

5.Ilmenite can be mined from both layered intrusive deposits and heavy mineral deposits. It is often found alongside rutile in heavy mineral deposits. Ilmenite is used to make titanium dioxide  pigment or it can be processed into feedstock that can be used in the manufacture of titanium. This has become more common as viable rutile deposits become increasingly scarce. South Africa and Australia are among the world’s largest producer of Ilmenite, each extracting over a million metric tonnes per year.

6.The Mining of titanium from intrusive rock is restricted to ilmenite and its weathered derivative leucoxene. The largest opencast ilmenite mine is Tellnes in Norway’s municipality of Sokndal.

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how many grams of oxygen reacted with 50.7f of potassium? how many molecules of potassium oxide are formed?​
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When an alkaline earth metal, a, reacts with a halogen, x, the formula of the covalent compund formed should be a2x?
Ierofanga [76]

Alkaline earth metal are the elements present in II group in the periodic table and are known as 'Metals' and have a charge of +2.

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Halogens - F, Cl, Br, I, At

When Alkaline earth metal (metals) combine with Halogens (non-metals) the compound formed will be ionic compound and the formula of the compound will be based on the charges of the element.

When we write the formula of the ionic compound the charges of the elements get criss crossed.

For example - Mg (Alkaline earth metal) have a charge of +2 and Cl (Halogen) have a charge of -1 and when they combine to form the formula their charges get criss crossed and we will get Mg_{1}Cl_{2} or MgCl_{2}

When an alkaline earth metal, A, reacts with a halogen, X, the formula of the Ionic compound formed should be AX_{2}


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3 years ago
2H20(g) → 2H2(g) + 02 (8)
fiasKO [112]

Answer:

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2 years ago
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

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3 years ago
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