The half-life of the radioactive substance can be determined through teh equation ln 2 = k (t 1/2) where k is equal to ln (1/(1-0.58)) / 3. Hence t 1/2 is equal to 2.40 days. To decay to 10% of the original amount, ln (1/0.90) / ( ln2) / 2.40, time is equal to 0.37 days.
Answer: I believe the answer is b. 55%
Step-by-step explanation:
200/ (550-200) * 100
Area of the full circle would be PI x r^2 = PI x 6^2 = 36 *3.14 = 113.04
the angle is 165
so area = 165/360 x 113.04
area = 51.8 in^2
answer is B
Answer:
2f+9
Step-by-step explanation:
Answer:
119
Step-by-step explanation:
