He can buy 5 of the $3 nut and 1 of the $5 nuts.
5x3=15
5x1=5
15+5=20 and that’s less than 24.
So Jim can use $20 to buy the $3 one 5 times and the $5 one 1 time.
There needs to be more information in order to solve your problem.
I'm sorry :(
Answer:
j = -3, -4
Step-by-step explanation:
j^2 + 7j + 12 = 0
(j + 3)(j + 4) = 0
j = -3, -4
Answer:
4.987 in
Step-by-step explanation:
Volume of a cube= (where x= side)
x³
we know that
124=x³
∛124=x
x=4.986630952 which rounds to
4.987
divisions between $389$ and $390$ so each division is $\frac{390-389}{10}=0.1$
A is 8 division from $389$, so, A is $389+8\times 0.1=389.8$
similarly, C is one division behind $389$ so it is $389-1\times 0.1=388.9$
and B is $390.3$
