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3 years ago

The quotient of a number and 7 is 32

Mathematics

1 answer:

ella [17]3 years ago

6 0

Answer:

=99=99=99=99=78

Step-by-step explanation:

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Does anyone need help

daser333 [38]

Me please !!!!!! MEEE

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2 years ago

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-5, 20, -80, 320, ... is a geometric sequence a. Find the common ratio, b. Write its recursive rule c. Write its explicit rule.W

mario62 [17]

In order to find the common ratio, we just need to divide a term by the term that comes before it.

So using the terms 20 and -5, we have:

$\text{ratio}=\frac{20}{-5}=-4$

The recursive rule can be found with the formula:

$a_n=a_{n-1}\cdot q$

Where an is the nth term and q is the ratio. So we have:

$a_n=a_{n-1}\cdot(-4)$

The explicit rule can be written as:

$a_n=a_1\cdot q^{n-1}$

Where an is the nth term, a1 is the first term and q is the ratio. So:

$a_n=-5\cdot(-4)^{n-1}$

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1 year ago

Write each phrase as an algebraic expression

Alekssandra [29.7K]

1. 15-x
2. 4y
These are algebraic expressions for both.

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3 years ago

A rental car company charges $15/day for a rental car plus 20¢ for every mile driven that day. Which equation models the relatio

nikdorinn [45]

<span>R=15d+0.20R=15d+0.20 is the answer</span>

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3 years ago

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The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio

zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0

3 years ago