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4 years ago

If a star’s radiation peaks in the ultraviolet region of the spectrum, what could you conclude?

Physics

2 answers:

Alex_Xolod [135]4 years ago

4 0

Answer:

It is a very intense star

Explanation:

As we know by Electromagnetic radiations the energy of spectrum in decreasing order is given as

1) Gamma Rays

2) X rays

3) Ultraviolet Rays

4) Visible Light

5) Infrared waves

6) Microwaves

7) Radio waves

So here we can say that ultraviolet rays are at peak intensity for the spectrum in the radiation which means major proportion of the spectrum is consisting this part of the electromagnetic waves

So here the star would be very intense due to large number of this spectrum.

PSYCHO15rus [73]4 years ago

3 0

The short answer is "it is a very intense star."

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Answer:

umm the lower the frequency the higher the pitch

Explanation:

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3 years ago

In an air conditioner, a substance that easily evaporates and condenses is used to transfer energy from a room to the air outsid

weeeeeb [17]

C. It transfer energy as heat to the surrounding air. This answer is incorrectly

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3 years ago

A boat is drifting with a speed of 5.0\,\dfrac{\text m}{\text s}5.0 s m 5, point, 0, space, start fraction, m, divided by, s,

zepelin [54]

Answer:

$d=42m(-\hat{i})$

Explanation:

For this problem, we need to apply the formulas of constant accelerated motion.

To obtain the boat displacement we need to calculate the displacement because of the river flow and the displacement done because of the boat motor.

for the river:

$d_r=v*t\\d_r=5m/s*6s\\d_r=30m(\hat{i})$

for the boat:

$x=\frac{1}{2}*a*t^2\\\\x=\frac{1}{2}*4.0m/s*(6s)^2\\\\\\x=72m(-\hat{i})$

So the final displacement is given by:

$d=dr+x\\d=30m-72m\\d=42m(-\hat{i})$

8 0

4 years ago

Read 2 more answers

A motorist travels at 270 km in p hours at a certain average speed. an expression for the distance that this motorist travelled

wel

Average speed = total distance / time ⇒ total distance = average speed * time

Average speed = 270 km / p hours
distance = d
hours = x

d = 270/p * x

5 0

4 years ago

A reconnaissance plane flies 560 km away from its base at 602 m/s, then flies back to its base at 903 m/s.

IrinaVladis [17]

Answer:

Approximately $722\; \rm m\cdot s^{-1}$ .

Explanation:

The average speed of a vehicle is calculated as:

$\displaystyle \text{average speed} = \frac{\text{total distance}}{\text{total time}}$ .

In this question, the total distance is $2 \times 560\; \rm km = 1120\; \rm km$ .

The unit of the speeds in this question is meters per second, while the unit of distance is kilometers. Convert the unit of distance to meters:

$560 \; \rm km = 560 \times 10^{3} \; \rm m = 5.6 \times 10^{5}\; \rm m$ .

$1120 \; \rm km = 1120 \times 10^{3} \; \rm m = 1.12 \times 10^{6}\; \rm m$ .

Time required for the first part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{602\; \rm m\cdot s^{-1}} \approx 930\; \rm s$ .

Time required for the second part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{903\; \rm m\cdot s^{-1}} \approx 620\; \rm s$ .

The time required for the entire trip would be approximately $930 + 620 = 1550\; \rm s$ .

Calculate the average speed of this plane:

$\begin{aligned} \text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &\approx \frac{1.12\times 10^{6}\; \rm m}{1550\; \rm s} \approx 722\; \rm m \cdot s^{-1}\end{aligned}$ .

6 0

3 years ago