Answer:
The speed of the spider is v = (2g*L*(1-cosθ))^1/2
Explanation:
using the energy conservation equation we have to:
Ek1 + Ep1 = Ek2 + Ep2
where
Ek1 = kinetic energy = 0
Ep1 = potential energy = m*g*L*cosθ
Ek2 = (m*v^2)/2
Ep2 = m*g*L
Replacing, we have:
0 - m*g*L*cosθ = (m*v^2)/2 - m*g*L
(m*v^2)/2 = m*g*L*(1-cosθ)
v^2 = 2g*L*(1-cosθ)
v = (2g*L*(1-cosθ))^1/2
Answer:
- Corey's max speed is

- the distance Corey's covers in z seconds is



Explanation:
<h3>Corey's max speed</h3>
For constant speed, we know:

The distance between the 80 meters and the 45 meters is:

and the time it took to reach the 80 meter will be:

So, Corey's max speed is

<h3>
How far runs Corey</h3>
As the velocity of Corey's is
, the distance Corey's covers in z seconds is


<h3>What is Corey's distance from the starting line</h3>
At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:


At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:


Answer:
China, US, India, and Russia