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Mars2501 [29]
3 years ago
10

A car with a mass of 1240kg starts from rest and accelerates to a speed of 19.4m/s in 10.2s. Assume that the force of resistance

remains constant at 376N during this time. What is the average power developed by the car's engine?
Physics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

Power, P = 38459.16 W

Explanation:

Given that,

Mass of a car, m = 1240 kg

Initial speed, u = 0

Final speed, v = 19.4 m/s

Time, t = 10.2 s

The resistance force, R = 376 N

We need to find the average power developed by the car's engine. It is given by the formula as follows :

P=F\times v\\\\P=(ma-R)v\\\\P=(\dfrac{mv}{t}-R)v\\\\P=(\dfrac{1240\times 19.4}{10.2}-376)\times 19.4\\\\P=38459.16\ W

So, the required power is 38459.16 watts.

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If you are driving 120 km/h along a straight road and you look to the side for 2.0 s , how far do you travel during this inatten
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120 km / 60 min

2 km / 1 min

1 km / 30 sec

0.5 km / 15 sec

0.03333 km / sec

0.03333 km = 33.33 m
8 0
3 years ago
You launch a baseball through the air at speed 37 m/sec, at angle 45 degrees above horizontal. Neglect air resistance. What shap
Marizza181 [45]

Answer:

Parabolic motion

Explanation:

It is given that,

Speed with which a baseball is launched through the ar, v = 37 m/s

Angle of projection, \theta=45^{\circ}

We know that when an object is projected with some initial speed having some angle of projection, the path followed by the object is called projectile motion. The object will act as a projectile here. As a result the shape of the trajectory will be parabolic.

The equation of parabolic path is given by :

y=tan\theta\ x-\dfrac{gx^2}{2u^2\ cos^2\theta}

It is similar to,

y=ax+bx^2 which is the equation of parabola

Hence, this is the required solution.                                                                                                    

6 0
3 years ago
Inthisexperiment,aspringforcewasusedtokeep moving object travelingin a circularpath.The size of a spring force should be proport
poizon [28]

Answer:

By calculation, it can be shown that;

K = \frac{F_{angular}}{2\times x\times c}

Whereby for constant K, as  {F_{angular}} increases,  x also increases.

Explanation:

The experiment set up consisted of the use of a spring force to maintain the object in  circular path.

The energy in the spring is given by

\frac{1}{2}\cdot k\cdot x^2.

Rotational kinetic energy = \frac{1}{2}·I·ω²

Inertia,  I =  \frac{1}{2}·m·r²

ω = \frac{v}{r}

Substituting gives

Rotational kinetic energy =  \frac{1}{2}·

=  \frac{1}{4}·m· v²

Equating both equations gives

K = \frac{2\times m\times v^2}{4\times x^{2} }  = \frac{1\times m\times v^2}{2\times x^{2} }  

Within the proportionality limit, x ∝ r

therefore we can write x = c·r which gives

\frac{ m\times v^2}{2\times x\times c\times r } = \frac{v^{2} }{r} \times\frac{m}{2\times x\times c}

Since \frac{v^{2} }{r} = angular acceleration, α, then

m× \frac{v^{2} }{r} = Angular force

Therefore K = \frac{F_{angular}}{2\times x\times c}

Therefore as Force, F increases, x also increases and the size of a spring force should be proportional to the amount of stretch in the spring.

3 0
3 years ago
Which of the following is least likely to result from seafloor spreading​
Assoli18 [71]

Answer:

An reversal in the magnetic fields of the north and south pole. This would be the most logical option for me...correct me if I'm wrong.

Explanation:

New seafloor is formed when magma is forced upward toward the surface at a mid-ocean.

7 0
3 years ago
When a dielectric slab is inserted between the plates of one of the two identical capacitors
tatiyna

Answer:(A-P,S;B-P,S;C-Q,S;D-P,S)

Solution

(A)→P,S,(B)→P,S,(C)→Q,S,(D)→P,S.

Explanation:

4 0
2 years ago
Read 2 more answers
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