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Mars2501 [29]
3 years ago
10

A car with a mass of 1240kg starts from rest and accelerates to a speed of 19.4m/s in 10.2s. Assume that the force of resistance

remains constant at 376N during this time. What is the average power developed by the car's engine?
Physics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

Power, P = 38459.16 W

Explanation:

Given that,

Mass of a car, m = 1240 kg

Initial speed, u = 0

Final speed, v = 19.4 m/s

Time, t = 10.2 s

The resistance force, R = 376 N

We need to find the average power developed by the car's engine. It is given by the formula as follows :

P=F\times v\\\\P=(ma-R)v\\\\P=(\dfrac{mv}{t}-R)v\\\\P=(\dfrac{1240\times 19.4}{10.2}-376)\times 19.4\\\\P=38459.16\ W

So, the required power is 38459.16 watts.

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A projectile is fired with initial speed vo at an angle of 45o above the horizontal. Assume no air resistance.
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The correct answer is a

Explanation:

At projectile launch speeds are

X axis     vₓ = v₀ = cte

Y axis     v_{y} = v_{oy} –gt

The moment is defined as

         p = mv

For the x axis

         pₓ = mvₓ = m v₀ₓ

As the speed is constant the moment is constant

For the y axis

        p_{y} = m v_{y} = m (v_{oy} –gt) = m v_{oy} - m (gt)

Speed ​​changes over time, so the moment also changes over time

Let's examine the answer

i   True

ii False.  The moment changes with time

The correct answer is a

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7 0
2 years ago
Which is a scientific claim?
forsale [732]

Answer:

D. Observations of constellations show that stars have moved over time.

Explanation:

A scientific claim is basically an observation in science.

Constellation changes there position over time because of earth's rotation around sun. So, observation of constellations shows that stars have moved over time is a scietific claim. If stars would not move then constellation will not form.

Hence, the correct answer is "of constellations show that stars have moved over time".

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2 years ago
What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosp
sineoko [7]

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

<h3>How to find the weight of a column of air?</h3>
  • As we know that the expression of pressure as,

                 P=\frac{F}{A}

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

  • It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

             P=1atm=1.013*10^5Pascals

  • From this, the value of weight will be,

            F=mg=P*A=1.013*10^5*4.5=4.56*10^5N

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

brainly.com/question/12830237

#SPJ4

4 0
1 year ago
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