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RideAnS [48]
2 years ago
11

In which type of circuit does charge move in only one direction?

Physics
1 answer:
Lesechka [4]2 years ago
3 0
C. A combined circuit
That’s the answer
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If you jumped out of a plane, you would begin speeding up as you fall downward. Eventually, due to wind resistance, your velocit
MrRa [10]

Answer:

Mg or your weight.

Explanation:

When your velocity is constant, the net force acting on you is 0. That means the upwards force of air resistance must fully balance the downwards force of gravity on you, which is Mg.

5 0
3 years ago
The ratio of output power to input power, in percent, is called?
Harrizon [31]
That's efficiency. There's no law that it must be stated in percent.
4 0
3 years ago
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A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground. What was the kinetic energy of the roc
Ahat [919]
2,450 Joules,  kinetic energy is 1/2 mass x velocity squared.
3 0
3 years ago
Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point to
Brut [27]

Answer:

It would point up.

Explanation:

Since I am at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward, the north pole of the compass would also point towards the earth's geographic north magnetic pole, since all other compasses point toward there.

Since the compass is free to swivel in any direction, the compass would point up, since it is at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward.

So, the compass would point up.

7 0
3 years ago
A speed boat moving at a velocity of 25 m/s runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its ra
mr_godi [17]
<h2>Answer:</h2>

The rate of deceleration is -0.14m/s^{2}

<h2>Explanation:</h2>

Using one of the equations of motion;

v = u + at

where;

v = final velocity of the boat = 0m/s (since the boat decelerates to a stop)

u = initial velocity of the boat = 25m/s

a = acceleration of the boat

t = time taken for the boat to accelerate/decelerate from u to v =   3 minutes

<em>Convert the time t = 3 minutes to seconds;</em>

=> 3 minutes = 3 x 60 seconds = 180seconds.

<em>Substitute the values of v, u, t into the equation above. We have;</em>

v =  u + at

=> 0 = 25 + a(180)

=> 0 = 25 + 180a

<em>Make a the subject of the formula;</em>

=> 180a = 0 - 25

=> 180a = -25

=> a = -25/180

=> a = -0.14m/s^{2}

The negative value of a shows that the boat is decelerating.

Therefore, the rate of deceleration of the speed boat is 0.14m/s^{2}

5 0
3 years ago
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