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vlada-n [284]
4 years ago
12

Decimal equivalent 45/54

Mathematics
2 answers:
olya-2409 [2.1K]4 years ago
6 0

Answer:

.8333333

Step-by-step explanation:

divide 45 by 54 and you get your answer

masha68 [24]4 years ago
3 0

Answer:

.8333333333333......... the 3 repeats to infinity

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The sale price of an item is $160 after a 20% off discount. What was the original price of the item?
bulgar [2K]

Answer:

200

Step-by-step explanation:

160/80 is 2. 2 times 100 is 200

6 0
3 years ago
Reducing fractions 5 to 30
Bumek [7]

Answer: 1 to 6 or 1/6

Step-by-step explanation:

5 to 30 is 5/30

simplify to 1/6 because both the 5 and 30 are divisible by 5

4 0
3 years ago
What is the slope of the line shown?
Anarel [89]

Hello!

\large\boxed{Slope = -\frac{1}{2}}

Use the slope formula along with provided points to solve for the slope.

We can use the points (-4, -1) and (0, -3) and plug these values into the equation:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3-(-1)}{0-(-4)} \\\\m = \frac{-2}{4} \\\\m = -\frac{1}{2}

4 0
3 years ago
Read 2 more answers
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 7/1+5x
S_A_V [24]

0

You compare the degrees of the numerator and the denominator.

The numerator has a degree of 0 and the denominator has a degree of 1.

Since the numerator < denominator the degree is 0.

6 0
3 years ago
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