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3 years ago

In Exercise,find the horizontal asymptote of the graph of the function. f(x) = 7/1+5x

Mathematics

1 answer:

S_A_V [24]3 years ago

6 0

You compare the degrees of the numerator and the denominator.

The numerator has a degree of 0 and the denominator has a degree of 1.

Since the numerator < denominator the degree is 0.

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A prize was awarded to 56 women and 642 men.

julia-pushkina [17]

My work to your question

3 0

3 years ago

Suppose a + b = 0.

Digiron [165]

I'm pretty sure that it's b. That's assuming that you find the negative of b^2 and not the square of negative b.

5 0

2 years ago

The perimeter of a rectangle is about 13.9 cm. If you double the width of the rectangle the perimeter is about 17.8 cm. Find the

fredd [130]

Answer:

5cm by 1.95cm

Step-by-step explanation:

Let the length of the rectangle be x

Let the width be y

Perimeter of a rectangle = 2x + 2y

If the initial perimeter of a rectangle is about 13.9 cm, then;

13.9 = 2x + 2y ..... 1

If when the width is double the perimeter is 17.8cm, then;

17.8 = 2x + 4y ..... 2

Subtract 1 from 2;

13.9 - 17.8 = 2y - 4y

- 3.9 = -2y

y = 3.9/2

y = 1.95 cm

Substitute y = 1.95 into 1 to get x;

From 1;

13.9 = 2x + 2y

13.9 = 2x + 2(1.95)

13.9 = 2x + 3.9

2x = 13.9-3.9

2x = 10

x = 5 cm

Hence the dimension of the smaller triangle is 5cm by 1.95cm

7 0

2 years ago

Work out the volume of this hemisphere with diameter 9.6 cm

weqwewe [10]

Answer:

Please refer to the attachment

7 0

2 years ago

Suppose 232subjects are treated with a drug that is used to treat pain and 50of them developed nausea. Use a 0.01significance le

Margarita [4]

Answer:

The correct option is B

$t = 0.6093$

$p-value = 0.27116$

The correct option is D

Step-by-step explanation:

From the question we are told that

The sample size is $n = 232$

The number that developed nausea is X = 50

The population proportion is p = 0.20

The null hypothesis is $H_o : p = 0.20$

The alternative hypothesis is $H_a : p > 0.20$

Generally the sample proportion is mathematically represented as

$\r p = \frac{50}{232}$

$\r p = 0.216$

Generally the test statistics is mathematically represented as

=> $t = \frac{\r p - p }{ \sqrt{ \frac{p(1- p )}{n} } }$

=> $t = \frac{ 0.216 - 0.20 }{ \sqrt{ \frac{ 0.20 (1- 0.20 )}{ 232} } }$

=> $t = 0.6093$

The p-value obtained from the z-table is

$p-value = P(Z > 0.6093) = 0.27116$

Given that the $p-value > \alpha$ then we fail to reject the null hypothesis

5 0

3 years ago