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german
3 years ago
9

Solve quadratic equation by factoring x^2-6x+9=0

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0
What you have to find is what numbers add to -6 and multiply to 9. these numbers would be -3 and -3 (-3+-3=-6, -3*-3=9). substitute these in for -6x as x^2-3x-3x+9=0. then factor out c and three to get x(x-3)-3(x-3)=0. x-3=0 in both cases, so x is three.
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Simplify 4 to the 7th over 5 squared all raised to the 3rd power.
Radda [10]
First write out your original equation.
{(\frac{ {4}^{7} }{ {5}^{2} } ) }^{3}
Then use the law of exponents(power of a power) to simplify.
\frac{ {4}^{21} }{ {5}^{6} }
(Multiply the numerator and denominator exponents by the outside power.)

The answer is 4 to the 21st over 5 to the 6th.
6 0
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16. Use the vertical line test to determine whether the relation is a function.
drek231 [11]

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neither of them are

Step-by-step explanation:

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2 years ago
Increase 50 kg by 10%
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Read 2 more answers
A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s
Bas_tet [7]

Answer:

Step-by-step explanation:

m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}

3 0
3 years ago
A ladder is resting against a wall. The ladder and the ground make an angle of 42.5° and the ladder is 10 feet long. How far awa
MA_775_DIABLO [31]
Cosα=x/L

x=Lcosα, we are told the ladder is 10ft and α=42.5 so

x=10cos42.5° ft

x≈7.37 ft (to nearest hundredth of a foot)

3 0
3 years ago
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