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german
3 years ago
9

Solve quadratic equation by factoring x^2-6x+9=0

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0
What you have to find is what numbers add to -6 and multiply to 9. these numbers would be -3 and -3 (-3+-3=-6, -3*-3=9). substitute these in for -6x as x^2-3x-3x+9=0. then factor out c and three to get x(x-3)-3(x-3)=0. x-3=0 in both cases, so x is three.
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Step-by-step explanation:

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We now composed the two functions to find:

(f\circ g)(x)=f(g(x))

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\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}

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We write this in interval notation as:

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We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of (f\circ g)(x) is

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

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