To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
Answer:
A
Step-by-step explanation:
Y intercept means x=0. f(0)=0-3=-3
g(0)=4
y intercept for f(x) is-3,y intercept for g(x)is 4
<h3>
Answer: 69.1 cm</h3>
Work Shown:
C = 2*pi*r
C = 2*3.14*11
C = 69.08
C = 69.1
This is the approximate distance around the circle, aka the perimeter.
Need more info: which one is the height? which is the lenght and which is width? and what type of prism is it?
