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worty [1.4K]
3 years ago
7

Solve the rational equation 5 divided by x equals quantity 4 times x plus 1 end quantity divided by x squared, and check for ext

raneous solutions.
x = 1; x = 0 is an extraneous solution
x = 0; x = 1 is an extraneous solution
x = −1; x = 0 is an extraneous solution
x = 0; x = −1 is an extraneous solution
Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

x =1,   x = 0 is extraneous.

Step-by-step explanation:

5/x = 4x + 1 / x^2

5x^2 = 4x^2 + x

5x^2 - 4x^2 - x = 0

x^2 - x = 0

x(x - 1) = 0

x = 0, 1.

x is not a solution because 5/x is undefined.

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