Answer:
Explanation:
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In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:
It means that the moles of acid can be computed given the volume and concentration of NaOH:
It means that the approximate molar mass of the acid is:
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Answer:
The pressure occupied is 1, 8 atm.
Explanation:
We use the Boyle´s Mariotte ´s law: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1= P2xV2. The unit of pressure is converted to mmHg in atm.
760 mmHg----1 atm
912 mmHg---x= (912 mmHg x 1 atm)/760 mmHg=1,2 atm
P1xV1= P2xV2
P2=P1xV1/V2= 1,2 atm x 12 L/ 8L= <em>1, 8 atm</em>
The answer to your question is the third option "1.079 kg/m<span>3
</span>"
<span>There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst.
4. Reduce pressure way below the limit 269 kPa.</span>
