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Yanka [14]
2 years ago
9

. The Henry's law constant for CO2 in water at 298 K

Chemistry
1 answer:
nikklg [1K]2 years ago
8 0

Answer:

henry didn't do th ebest of the rome nation

Explanation:

henry didn't do th ebest of the rome nation

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The definition of chemical symbol
frozen [14]
<span>an abbreviation or short representation of a chemical element; thesymbols in the periodic table</span><span>
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If 2 or more elements are involved in a chemical reaction, they will most likely form a/an
wlad13 [49]

the correct answer would be mixture because compound uses the same element

8 0
3 years ago
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}      ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

We are given:

M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL

Putting values in above equation, we get:

0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g

Hence, the mass of glucose in final solution is 1.085 grams

4 0
3 years ago
Identify the single displacement reaction. C4H12 + 7O2 ⟶ 6H2O + 4CO2 2H2 + O2 ⟶ 2H2O Al2S3 ⟶ 2Al + 3S Cl2 + 2KBr ⟶ 2KCl + Br2
Varvara68 [4.7K]

Answer:- Cl_2+2KBr\rightarrow 2KCl+Br_2

Explanations:-  The first reaction is combustion reaction as the hydrocarbon is burned in presence of oxygen to give carbon dioxide and water.

Second reaction is the synthesis reaction as in general a synthesis reaction looks like:

A+B\rightarrow AB

Third reaction is the decomposition reaction as it looks opposite of synthesis reaction.

AB\rightarrow A+B

In general, a single displacement reaction looks like:

AB+C\rightarrow AC+B

Fourth reaction is single replacement reaction as bromine is replaced by chlorine.

So, the correct choice is the last reaction, Cl_2+2KBr\rightarrow 2KCl+Br_2 .

8 0
3 years ago
What greek letter are used in the precise definition of a limit?
Ivan
Epsilon-delta would be the green letter that is used in the precision definition of a limit. (ε, δ).
5 0
3 years ago
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