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3 years ago

You normally take 2 Ibuprofen (C13H18O2) when you have pain. Each one is 250 g. How many moles of ibuprofen do you take?

Chemistry

1 answer:

weqwewe [10]3 years ago

4 0

Answer:

2.4mol

Explanation:

In order to calculate numbers of moles we have to divide the given mass by the molar mass of the substance (ibuprofen) n= m/M

To calculate the molar mass we have

C13= 12*13= 156

H18= 1*18=18

O2= 16*2 =32

Molar mass M = 153+18+32= 206g

Given the mass m= 250g per tablet

Hence number of moles in one tablet is n= 250/206= 1.2 mol

Therefore the total number of ibuprofen you took is 1.2*2 (for the two tablets) = 2.4 moles

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What is the volume of water in 150ml of the 35% of sucrose with a specific gravity of 1.115?

anzhelika [568]

Answer:

The volume of the water is 108.71 mL

Explanation:

Step 1: Data given

Volume of water =150 mL = 0.150 L

concentration of sucrose solution 35 % w/w this means in 100 grams of water we have 35 grams of sucrose

specific gravity =1.115

Step 2: Calculate the density of the solution

Density = specific gravity * density of water

Density of solution = 1.115 * 1g/ mL

Density of solution = 1.115 g/ mL

Step 3: Calculate mass of the solution

Mass of solution = density ¨volume

Mass of solution = 1.115 g/ mL * 150 mL

Mass of solution = 167.25 grams

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3 years ago

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Which vein carries oxygenated blood back into the heart?

Finger [1]

Answer:

The veins that carry oxygenated bloof back into the heart are the pulmonary arteries.

Explanation:

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A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 3

ELEN [110]

Answer:

The volume of the gas sample at standard pressure is <u>819.5ml</u>

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

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$V_2=?$

$P_{total}=735 mmhg$

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

$P_{water}=42.2mmhg$

$T_1=35°C=35+273=308 K$

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

$P_{gas}=P_{total}-P_{water}$

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

$\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}$

$V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1$

$V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1$

Here $P_2 \:and\: T_2$ are standard pressure and temperature respectively.

we have

$P_2=750mmhg \:and\: T_2=273K$

Substituting value, we get

$V_2=\frac{692.8}{750}*\frac{273}{308} *250$

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Answer:

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