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djyliett [7]
3 years ago
11

A patient is receiving treatments for brain cancer. Which electromagnetic waves are most likely being used as part of the treatm

ent?
A)infrared
B)ultraviolet
C)microwave
D)gamma ray
Chemistry
2 answers:
Lostsunrise [7]3 years ago
6 0

Answer;

D) Gamma ray

Explanation;

-Electromagnetic Waves may help fight Brain cancer. The use of electromagnetic radiations or waves to treat cancer is called radiation therapy, in which cancer treatment uses high doses of radiations to kill cancer cells and shrink tumors.

-Gamma rays or gamma radiations are the main electromagnetic radiations used for this radiation therapy.

SVETLANKA909090 [29]3 years ago
5 0
Gamma rays, or rather gamma radiation are most commonly used.
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Can you show me the answer and explain?
Hitman42 [59]

Answer:

C

Explanation:

looking at a periodic table X is fluorine and Y is potassium

Fluorine is in group 7 and forms a 1- charge (which gains electrons) and potassium is in group 1 and forms a 1+ charge (which loses electrons)

Fluorine (X) has an electronic structure of 2,7 and needs to gain an electron from Potassium (Y) to have a full outer shell and potassium has an electronic structure of 2,8,8,1 so needs to lose an electron to have a full outer shell as well. This means that the electron that potassium (Y) has lost is given away to fluorine (X), so both elements become stable.

This is known as ionic bonding where metals (like potassium) lose electrons and non-metals (like fluorine) gain electrons to become more stable, forming ions

Any further clarification let me know

6 0
2 years ago
How far can you travel in 7 hours if you are driving at a rate of 55 mph
Oksi-84 [34.3K]

the answer is 385 miles

5 0
3 years ago
What is the best way to measure the age of the Earth and why? Explain how scientists do this.
UkoKoshka [18]

Explanation:

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3 0
3 years ago
How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??
GarryVolchara [31]
The atoms  of  hydrogen  that are  present  in  7.63 g  of ammonia(NH3)

find  the  moles  of NH3 =mass/molar mass
 7.63 g/ 17 g/mol = 0.449  moles

since there  is  3 atoms of H  in NH3 the  moles of  H = 0.449 x 3 = 1.347 moles

by  use  of  1 mole = 6.02 x10^23  atoms
what  about  1.347  moles

= 1.347  moles/1   moles  x 6.02 x10^23 atoms = 8.11 x10^23  atoms of Hydrogen
3 0
3 years ago
Can anyone check my work and see if it is correct? If not, may someone help me?
shusha [124]
It looks all correct to me, great job!
6 0
3 years ago
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