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3 years ago

Find x. and rounddddd

Mathematics

1 answer:

Lerok [7]3 years ago

6 0

Answer:

X=117.9

Step-by-step explanation:

I got itttt

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15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find dy/dx at =22/7*4

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

It looks like we're given

$\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}$

where a and b are presumably constant.

Recall that

$\cos^2t=\dfrac{1+\cos(2t)}2$

$\sin^2t=\dfrac{1-\cos(2t)}2$

so that

$\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}$

Then we have

$\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t$

$\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}$

$\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}$

where the last reduction follows from dividing through everything by $\cos(2t)\cos^2t$ and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0

3 years ago

(15 points please help)

dsp73

C. You can graph it on Desmos and all the given points work.

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Solve the inequality. 3≤7+g

Anastaziya [24]

Answer:

g-4

Step-by-step explanation:

first subtract 7 from both sides

then you will get -4 $\leq$ g

which is the same as g $\geq$ -4

you just have to switch them

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What is a factor in whole numbers and fractions?

harkovskaia [24]

Mixed fraction is what it is called
Mixed fraction factor: 1(1/2)
Normal fraction factor:4/2
U can use 4/2 or 2

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3 years ago

Which expression is equivalent to (3/4)^-2 A: -9/16 B: 16/9 C: -6/8 D: 9/16

UkoKoshka [18]

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