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Sedbober [7]
3 years ago
13

(0,8), m = -4 solve for m what is the slope

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0
M = -4 

you already gave us the answer.
You might be interested in
What is the range of the function y=3 Sqrt x+8
ValentinkaMS [17]

Answer:

(-\infty,+\infty)

Step-by-step explanation:

The given function is

y=\sqrt[3]{x+8}

The range refers to the values of y for which  x is defined.

We solve for x to obtain;

y^3=x+8

x=y^3-8

This is a polynomial function in y.

x is defined for all values of y.

Therefore the range is all real numbers.

or

(-\infty,+\infty)

The first choice is correct.

4 0
3 years ago
Read 2 more answers
HELP I WILL MARK YOU AS A BRAINLIEST!!!
klasskru [66]

They give you the base value which makes this easy, the answer is B. 32, because 8 times 4 is 32.

Hope this helps, if not, comment below please!!!!

6 0
3 years ago
Half an hour after leaving her house Beverly was 20 miles from home. At this point she merged onto the highway and was traveling
N76 [4]

Answer:

1. 45.71 miles

2. 10 miles

3. 89.43 miles

4. 0.79 hr

5. 0.025 hr

Step-by-step explanation:

speed = distance/time

After 4 hrs Beverly was 200 miles from home , however she had spent 0.5hr travelling for 20 miles prior to getting to the highway.

Therefore;

Constant speed before Highway = 20/0.5 = 40 miles/hr

Constant speed at Highway = \frac{(200-20)}{(4-0.5)} = 51.43 miles/hr

1. in 1 hr beverly will have travelled;

⇒ (20 miles in 0.5 hr ) + (0.5 hr  at speed 51.43 miles/hr)

⇒ 20 + (0.5 x 51.43) = 45.71 miles

2. In 0.25 hr beverly had not reached the highway

⇒ distance = speed x time

⇒ distance = 40 x 0.25 = 10 miles

3. in 1.85 hrs beverly will have travvelld;

⇒ (20 miles in 0.5 hr ) + (1.35 hr at speed 51.43 miles/hr)

⇒ 20 + 69.43 = 89.43 miles

4. Time taken to get to 35 miles

⇒ (20 miles in 0.5 hr ) + (15 miles  at speed 51.43 miles/hr)

⇒ 0.5hr + (15/51.43) hr = 0.79 hr

5. Time taken to travel 1 mile

 ⇒ time = distance / speed = 1 mile  / 40 miles/hr

⇒ time = 0.025 hr

8 0
3 years ago
19) A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
ElenaW [278]

Answer:

29.4 meters

Step-by-step explanation:

Given the following :

A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

distance it moved between two positions. Use the "distance on the number line "formula

Initial Position or distance of submarine before ascension = 56.8 meters

Final position after ascension = 27.4 meters

The distance moved by the submarine between the two positions can be obtained by.

(Initial distance - Final distance)

(56.8 - 27.4) = 29.4 meters

5 0
3 years ago
X/2 is greater than or equal to -4
irga5000 [103]
\frac{x}{2}≥-4

Pretend the greater than or equal to sign is an equal sign, we will substitute it back in later.

x/2 = -4
Multiply both sides by 2 to get x alone
x = -8
Substitute the greater than or equal to sign back in and voila!
x≥-8
3 0
3 years ago
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