What is the result when the number 60 is increased by 60%

Mathematics

1 answer:

otez555 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

A quick but accurate way to approach this question would be to multiply 60 by 1.60. We get 1.60(60) = 96.

Note that 1(60) = 60, and that 0.60(60) = 36, and that 60 + 36 = 96. The earlier method is faster.

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What is the measure of ACB in O below?

Nezavi [6.7K]

Answer:

Step-by-step explanation:

The central angle is equal to the arc that subtends it , then

arc AB = 30°

arc ACB = 360° - 30° = 330° → A

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2 years ago

Today is sunday. Tom starts to read a book with 490 pages today. Sundays he reads 25 pages and on all other days he reads 4 page

mrs_skeptik [129]

Based on the information given, it can be noted that Tom will use 117 days to read the book.

How to solve a equation.

Based on the information given, we are informed that Tom starts to read a book with 490 pages today. Sundays he reads 25 pages and on all other days he reads 4 pages.

Let the number of days be represented by x. Therefore, the equation to solve the question will be:

25 + (4 × x) = 490

25 + 4x = 490

4x = 490 - 25

4x = 465

x = 465/4

x = 116.25

x = 117

Therefore, he'll use 117 days to read the book.

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brainly.com/question/13763238

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2 years ago

How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$