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juin [17]
3 years ago
15

Captain Two-Pegs is going to load his pirate ship with cannons. He has room for 10 cannons. He has allotted for 111 pounds of ca

nnon on his ship. He can choose from 9-pound cannons (the variable n) or 12-pound cannons (the variable t). Which equations would be a constraint to Captain Two-Pegs maximizing his cannon load?
(a) n - t = 10
(b) n = 10 + t
(c) 9n = 111 - 12t
(d) 9n = 111 + 12t
Mathematics
2 answers:
mr_godi [17]3 years ago
6 0
9n + 12t = 111
9n = 111 - 12t
stepan [7]3 years ago
3 0

Answer:

C. 9n=111-12t

Step-by-step explanation:

Let us assume that,

n is the number of 9-pound cannons and,

t is the number of 12-pound canons.

As captain Two-Pegs has room for 10 cannons, so

n+t=10 ---------------------------1

He has allotted for 111 pounds of cannon on his ship, so

9n+12t=111    -------------------2

i.e 9n=111-12t

Therefore, option 3 is the equations that would be a constraint to Captain Two-Pegs maximizing his cannon load.


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2 years ago
Bethany,Lauren,Amanda,and David all meet at Family reunion. They are comparing their ages. They have found that Laura is 13 year
bazaltina [42]
The second system of equations, 

\left \{ {{y=\frac{x^2}{2}+\frac{13}{2}x} \atop {y=x^2-27x+129}}
is correct.

We know that Bethany's age is x.  Since Laura is 13 years older, her age is x+13.  The product of their ages is equal to twice Amanda's age, and Amanda's age is y.  This gives us:
x(x+13) = 2y

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x²+13x=2y

Dividing everything by 2 (to isolate y), we have:
x²/2 + (13/2)x = y

If we take 20 years off of Bethany's age, it is now represented as x-20.  Taking 20 years off of Laura's age would be (x+13-20) or x-7.  The product of their ages now is equal to David's age; David is 11 years older than Amanda, so his age is y+11.  This gives us:

(x-20)(x-7)=y+11

Multiplying the binomials we have:"
x*x - 7*x - 20*x - 20(-7) = y+11
x²-7x-20x--140=y+11
x²-27x+140=y+11

To isolate y, subtract 11 from both sides:
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7 0
3 years ago
15 points and will mark brainliest
rewona [7]
Solve the following system:{-9 x = 5 - 2 y | (equation 1)15 x = 2 y - 11 | (equation 2)
Express the system in standard form:{-(9 x) + 2 y = 5 | (equation 1)15 x - 2 y = -11 | (equation 2)
Swap equation 1 with equation 2:{15 x - 2 y = -11 | (equation 1)-(9 x) + 2 y = 5 | (equation 2)
Add 3/5 × (equation 1) to equation 2:{15 x - 2 y = -11 | (equation 1)0 x+(4 y)/5 = (-8)/5 | (equation 2)
Multiply equation 2 by 5/4:{15 x - 2 y = -11 | (equation 1)0 x+y = -2 | (equation 2)
Add 2 × (equation 2) to equation 1:{15 x+0 y = -15 | (equation 1)0 x+y = -2 | (equation 2)
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Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.

4 0
3 years ago
Which statement is true about this equation?
Nana76 [90]

Answer:

C

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<u>Distribute</u><u>:</u>

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weqwewe [10]

Answer:

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This means that, a vertical line drawn across the entire graph will intersect the graph of these functions at more than one point.

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