I’m a bit confused by the choices you have been given. Are there any other options? If not, I would choose (5.3,9.8) as 9.8 is correct
Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) =
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
Answer:
Step-by-step explanation:
We first need to find the slope of the given line. Putting that standard form of a line into slope intercept:
12y = -3x - 6 so

In this form we can easily determine that our slope is -1/4. That means that the perpendicular slope, the opposite reciprocal, is +4. We will write first the point slope of the new line using our given point, then solve it for y, putting it into slope-intercept form. y - (-7) = 4(x - (-1)) and
y + 7 = 4x + 4 so
y = 4x + 4 - 7 so
y = 4x - 3
The answer should be OC. Major Axis
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